tag:blogger.com,1999:blog-13900197.post1146613507593980836..comments2023-10-15T05:20:00.675-06:00Comments on Entropy Production: The Aluminium-Hydrogen ConceptRobert McLeodhttp://www.blogger.com/profile/05270962906437456350noreply@blogger.comBlogger6125tag:blogger.com,1999:blog-13900197.post-475477820142246982008-07-10T11:40:00.000-06:002008-07-10T11:40:00.000-06:00Your a little out of date the latest mix is down t...Your a little out of date the latest mix is down to around 20% gal with a small amount of indium and tin. The Aluminium in the new mix it closer to 75%Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-13900197.post-50335560952065987382008-05-03T07:43:00.000-06:002008-05-03T07:43:00.000-06:00All false,First of all, the water split reaction d...All false,<BR/><BR/>First of all, the water split reaction does not create alumina but AL(OH)3. And efficiency of aluminium electrolysis is close to 94% these days.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-13900197.post-45364660312817625492008-01-21T09:52:00.000-07:002008-01-21T09:52:00.000-07:00I think there is actually a mistake. In my opinion...I think there is actually a mistake. <BR/>In my opinion: <BR/>exothermical : <BR/>2 Al + 3 / 2 O2 -> Al2O3 + 1672 [kJ / mol (Al2O3)] (exothermic) <BR/>endothermical :<BR/>H2O -> H2 + O -285.8 [kJ / mol (H2)]<BR/>=> (3 for moles): 3 H2O -> 3 H2 + 3 / 2 O2 -857.4 [kJ] <BR/>Finally: 2 Al + 3 H2O -> Al2O3 + 3 H2 + 1672-857.4 = 817.6 [kJ] <BR/>The process efficiency is about 50% (857.4/1672) <BR/>But the Al electrolysis has also 50% efficiency too => about 25% for the complete process, without the fuel cell or the thermical motor. <BR/>A second point is that the electrolysis burn about 415 kg of Carbon for each 1'000 kg of Al (electrodes)! <BR/>That's the real bad deal ... <BR/>PS Excuse me for my bad english.jeandaniel217https://www.blogger.com/profile/12567416628168202014noreply@blogger.comtag:blogger.com,1999:blog-13900197.post-44897108001044258852007-07-11T04:51:00.000-06:002007-07-11T04:51:00.000-06:00Shouldn't this be 4 Al (bulk) + 3 H2O → 2 Al2O3 + ...Shouldn't this be <BR/><BR/>4 Al (bulk) + 3 H2O → 2 Al2O3 + 3 H2Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-13900197.post-70429177910450416572007-06-26T11:09:00.000-06:002007-06-26T11:09:00.000-06:00No, those are all correct.No, those are all correct.Robert McLeodhttps://www.blogger.com/profile/05270962906437456350noreply@blogger.comtag:blogger.com,1999:blog-13900197.post-29819502494823417952007-06-23T17:16:00.000-06:002007-06-23T17:16:00.000-06:00IANAC, but I think you need to reverse the sign on...IANAC, but I think you need to reverse the sign on the second equation, but it still a bad deal.Fat Manhttps://www.blogger.com/profile/09554029467445000453noreply@blogger.com